Class 11 Physics

Chapter: Motion in a Straight Line

JEE Advanced Level MCQs

Q1. A particle moves along the x-axis according to x = 4t³ − 6t² + 3t + 2. Find acceleration at t = 2 s.

A) 24 m/s²

B) 36 m/s²

C) 48 m/s²

D) 12 m/s²

View Solution

v = dx/dt = 12t² − 12t + 3

a = dv/dt = 24t − 12

At t = 2 s, a = 24(2) − 12 = 36 m/s²

Answer: B

Q2. A car moving with speed 20 m/s is brought to rest uniformly in 5 seconds. Distance travelled is:

A) 25 m

B) 50 m

C) 75 m

D) 100 m

View Solution

s = ((u + v)/2) × t

= ((20 + 0)/2) × 5 = 50 m

Answer: B

Q3. A particle starts from rest and moves with acceleration 4 m/s². Distance covered in 5th second is:

A) 10 m

B) 18 m

C) 20 m

D) 22 m

View Solution

Sₙ = u + (a/2)(2n − 1)

= 0 + (4/2)(9) = 18 m

Answer: B

Q4. A train 200 m long crosses a pole in 20 s. Speed of train is:

A) 5 m/s

B) 10 m/s

C) 15 m/s

D) 20 m/s

View Solution

Speed = Distance / Time = 200/20 = 10 m/s

Answer: B

Q5. A body starting from rest acquires velocity 20 m/s in 4 seconds. Distance travelled is:

A) 20 m

B) 30 m

C) 40 m

D) 50 m

View Solution

s = ((u + v)/2)t = ((0 + 20)/2) × 4 = 40 m

Answer: C

Q6. A particle moves according to x = t³ − 6t² + 9t. The particle changes direction at:

A) 1 s

B) 2 s

C) 3 s

D) Both A and C

View Solution

v = 3t² − 12t + 9

For change in direction, v = 0

3(t² − 4t + 3)=0 ⇒ (t−1)(t−3)=0

t = 1 s and 3 s

Answer: D

Q7. The slope of velocity-time graph gives:

A) Velocity

B) Displacement

C) Acceleration

D) Momentum

View Solution

Slope of velocity-time graph represents acceleration.

Answer: C

Q8. A body covers first half of distance with speed v and second half with speed 2v. Average speed is:

A) 3v/2

B) 4v/3

C) 2v/3

D) v

View Solution

For equal distances, Vavg = 2v₁v₂/(v₁+v₂)

= 2(v)(2v)/(v+2v) = 4v/3

Answer: B

Q9. A train 200 m long crosses a pole in 20 s. Speed of train is:

A) 5 m/s

B) 10 m/s

C) 15 m/s

D) 20 m/s

View Solution

Speed = Distance / Time = 200/20 = 10 m/s

Answer: B

Q10. A particle starts from rest and moves with acceleration 4 m/s². Distance covered in 5th second is:

A) 10 m

B) 18 m

C) 20 m

D) 22 m

View Solution

Sₙ = u + (a/2)(2n − 1)

= 0 + (4/2)(9) = 18 m

Answer: B

Q11. A particle moving with velocity 30 m/s is retarded uniformly at 5 m/s². Time to stop is:

A) 5 s

B) 6 s

C) 7 s

D) 8 s

View Solution

v = u + at

0 = 30 − 5t ⇒ t = 6 s

Answer: B

Q12. The area under acceleration-time graph gives:

A) Velocity

B) Displacement

C) Force

D) Momentum

View Solution

Area under acceleration-time graph represents change in velocity.

Answer: A

Q13. A particle moves with acceleration a = 6t. If initial velocity is zero, velocity at 2 s is:

A) 6 m/s

B) 8 m/s

C) 10 m/s

D) 12 m/s

View Solution

v = ∫6t dt = 3t²

At t = 2 s, v = 3(2²)=12 m/s

Answer: D

Q14. A body moving with uniform acceleration has velocities 10 m/s and 30 m/s at distances 5 m and 25 m respectively from origin. Acceleration is:

A) 10 m/s²

B) 20 m/s²

C) 15 m/s²

D) 25 m/s²

View Solution

v² − u² = 2as

30² − 10² = 2a(25−5)

800 = 40a ⇒ a = 20 m/s²

Answer: B

Q15. A particle moves along x-axis as x = 5 + 2t − 3t². The particle changes direction at:

A) 1/3 s

B) 2/3 s

C) 1 s

D) 2 s

View Solution

v = dx/dt = 2 − 6t

For change in direction, v = 0

2 − 6t = 0 ⇒ t = 1/3 s

Answer: A

Q16. If velocity-time graph is a straight line parallel to time axis, acceleration is:

A) Positive

B) Negative

C) Zero

D) Infinite

View Solution

Slope of velocity-time graph gives acceleration. Parallel line means slope = 0.

Answer: C

Q17. A stone is dropped from a height of 80 m. Time taken to reach ground is (g = 10 m/s²):

A) 2 s

B) 3 s

C) 4 s

D) 5 s

View Solution

s = ½gt²

80 = 5t² ⇒ t² = 16 ⇒ t = 4 s

Answer: C

Q18. A particle travels 10 m in first second and 15 m in second second. Acceleration is:

A) 2.5 m/s²

B) 5 m/s²

C) 7.5 m/s²

D) 10 m/s²

View Solution

For uniformly accelerated motion, difference of distances in successive seconds equals acceleration.

a = 15 − 10 = 5 m/s²

Answer: B

Q19. A body moves with velocity proportional to time: v = kt. Displacement-time graph is:

A) Straight line

B) Circle

C) Parabola

D) Hyperbola

View Solution

v = ds/dt = kt

s = ∫kt dt = kt²/2

This represents a parabola.

Answer: C

Q20. A body starting from rest acquires velocity 20 m/s in 4 seconds. Distance travelled is:

A) 20 m

B) 30 m

C) 40 m

D) 50 m

View Solution

s = ((u + v)/2)t

= ((0 + 20)/2) × 4 = 40 m

Answer: C

Q21. A particle moving along x-axis has x = t² − 4t + 4. Minimum value of x is:

A) 0

B) 1

C) 2

D) 4

View Solution

x = t² − 4t + 4 = (t − 2)²

Minimum x = 0

Answer: A

Q22. A train accelerates uniformly from 10 m/s to 30 m/s in 10 s. Distance travelled is:

A) 100 m

B) 150 m

C) 200 m

D) 250 m

View Solution

s = ((u + v)/2)t = ((10 + 30)/2) × 10 = 200 m

Answer: C

Q23. The dimensional formula of acceleration is:

A) [LT⁻¹]

B) [LT⁻²]

C) [L²T⁻²]

D) [MLT⁻²]

View Solution

Acceleration = Velocity / Time

[LT⁻¹]/[T] = [LT⁻²]

Answer: B

Q24. A body moving with uniform acceleration covers 100 m in 5 s and 180 m in next 5 s. Acceleration is:

A) 1.6 m/s²

B) 2 m/s²

C) 3.2 m/s²

D) 4 m/s²

View Solution

Difference in equal time intervals = aT²

180 − 100 = a(5²)

80 = 25a ⇒ a = 3.2 m/s²

Answer: C

Q25. The speed-time graph of a particle is a straight line with negative slope. Motion is:

A) Uniform motion

B) Accelerated motion

C) Retarded motion

D) Circular motion

View Solution

Negative slope in speed-time graph indicates retardation.

Answer: C

Q26. A particle starts with velocity 5 m/s and acceleration 2 m/s². Velocity after travelling 12 m is:

A) 5 m/s

B) 7 m/s

C) 9 m/s

D) 11 m/s

View Solution

v² = u² + 2as

v² = 5² + 2(2)(12)=25+48=73

v ≈ 8.5 m/s, closest option = 9 m/s

Answer: C

Q27. A body moving with speed 15 m/s comes to rest after travelling 45 m. Retardation is:

A) 1.5 m/s²

B) 2.5 m/s²

C) 3.5 m/s²

D) 4.5 m/s²

View Solution

v² = u² + 2as

0 = 15² + 2a(45)

0 = 225 + 90a ⇒ a = −2.5 m/s²

Retardation = 2.5 m/s²

Answer: B

Q28. A particle covers equal distances in equal intervals of time. Its motion is:

A) Uniformly accelerated

B) Uniform

C) Retarded

D) Non-uniform

View Solution

Equal distances in equal intervals define uniform motion.

Answer: B

Q29. The intercept on velocity axis in velocity-time graph represents:

A) Acceleration

B) Final velocity

C) Initial velocity

D) Displacement

View Solution

At t = 0, velocity-time graph gives initial velocity.

Answer: C

Q30. A body moving with acceleration 5 m/s² increases its velocity from 10 m/s to 30 m/s. Time taken is:

A) 2 s

B) 3 s

C) 4 s

D) 5 s

View Solution

v = u + at

30 = 10 + 5t ⇒ t = 4 s

Answer: C

Q31. A particle moves with constant speed in a straight line. Its acceleration is:

A) Constant

B) Increasing

C) Zero

D) Infinite

View Solution

Velocity remains constant in magnitude and direction, so acceleration is zero.

Answer: C

Q32. A body falls freely from rest. Distance covered in 3rd second is:

A) 15 m

B) 25 m

C) 35 m

D) 45 m

View Solution

Sₙ = (g/2)(2n − 1)

= (10/2)(2×3 − 1)=5×5=25 m

Answer: B

Q33. A particle has acceleration-time graph parallel to time axis above it. Motion is:

A) Uniform velocity

B) Constant acceleration

C) Variable acceleration

D) Retardation

View Solution

A horizontal line above time axis means acceleration is constant and positive.

Answer: B

Q34. A body moving at 25 m/s is slowed uniformly to 5 m/s in 10 s. Acceleration is:

A) −1 m/s²

B) −2 m/s²

C) −3 m/s²

D) −4 m/s²

View Solution

a = (v − u)/t = (5 − 25)/10 = −2 m/s²

Answer: B

Q35. If displacement-time graph is a straight line, velocity is:

A) Variable

B) Zero

C) Constant

D) Infinite

View Solution

Slope of displacement-time graph gives velocity. Straight line means constant slope.

Answer: C

Q36. A particle moves such that v = 3t + 2. Displacement in first 2 seconds is:

A) 8 m

B) 10 m

C) 12 m

D) 14 m

View Solution

s = ∫(3t + 2)dt from 0 to 2

= [3t²/2 + 2t]₀² = 6 + 4 = 10 m

Answer: B

Q37. A train moving at 72 km/h is brought to rest in 20 s. Retardation is:

A) 0.5 m/s²

B) 1 m/s²

C) 1.5 m/s²

D) 2 m/s²

View Solution

72 km/h = 20 m/s

a = (0 − 20)/20 = −1 m/s²

Retardation = 1 m/s²

Answer: B

Q38. The SI unit of velocity is:

A) m

B) m/s

C) m/s²

D) km/h

View Solution

SI unit of velocity is metre per second.

Answer: B

Q39. A particle starts from rest with acceleration 3 m/s². Velocity after 6 s is:

A) 12 m/s

B) 15 m/s

C) 18 m/s

D) 21 m/s

View Solution

v = u + at = 0 + 3×6 = 18 m/s

Answer: C

Q40. A body covers 20 m in first 2 s and 40 m in next 2 s. Motion is:

A) Uniform

B) Accelerated

C) Retarded

D) Circular

View Solution

Distance covered increases in equal intervals of time, so motion is accelerated.

Answer: B

Q41. The area under velocity-time graph represents:

A) Acceleration

B) Force

C) Displacement

D) Momentum

View Solution

Area under velocity-time graph gives displacement.

Answer: C

Q42. A particle moves with acceleration −4 m/s². If initial velocity is 20 m/s, time to stop is:

A) 2 s

B) 4 s

C) 5 s

D) 8 s

View Solution

v = u + at

0 = 20 − 4t ⇒ t = 5 s

Answer: C

Q43. A body travels with uniform acceleration. Ratio of distances covered in 1st, 2nd and 3rd seconds is:

A) 1 : 2 : 3

B) 1 : 3 : 5

C) 1 : 4 : 9

D) 2 : 3 : 4

View Solution

Distance in nth second is proportional to (2n − 1). Ratio = 1 : 3 : 5

Answer: B

Q44. A particle has constant velocity. Which statement is true?

A) Acceleration constant

B) Acceleration zero

C) Force infinite

D) Speed variable

View Solution

Constant velocity means no change in velocity. Hence acceleration is zero.

Answer: B

Q45. A particle moves according to x = 2t² + 3t + 1. Velocity at t = 2 s is:

A) 7 m/s

B) 9 m/s

C) 11 m/s

D) 13 m/s

View Solution

v = dx/dt = 4t + 3

At t = 2, v = 8 + 3 = 11 m/s

Answer: C

Q46. A body moving uniformly covers 120 m in 8 s. Speed is:

A) 10 m/s

B) 12 m/s

C) 15 m/s

D) 20 m/s

View Solution

Speed = Distance / Time = 120/8 = 15 m/s

Answer: C

Q47. A particle starts from rest and moves with acceleration 2 m/s². Distance travelled in 10 s is:

A) 50 m

B) 100 m

C) 150 m

D) 200 m

View Solution

s = ½at² = ½ × 2 × 10² = 100 m

Answer: B

Q48. The graph of displacement versus time for uniform motion is:

A) Circle

B) Straight line

C) Parabola

D) Hyperbola

View Solution

Uniform motion means constant velocity; displacement-time graph is a straight line.

Answer: B

Q49. A body initially at rest acquires acceleration 4 m/s². Distance covered in 3 s is:

A) 12 m

B) 16 m

C) 18 m

D) 20 m

View Solution

s = ½at² = ½ × 4 × 3² = 18 m

Answer: C

Q50. A particle moving with speed 40 m/s is uniformly retarded at 8 m/s². Distance travelled before stopping is:

A) 80 m

B) 100 m

C) 120 m

D) 140 m

View Solution

v² = u² + 2as

0 = 40² + 2(−8)s

0 = 1600 − 16s ⇒ s = 100 m

Answer: B

Class 11 Physics

Chapter: Motion in a Straight Line

50 MCQs with Answers and View Solution

Q1. A particle moves along the x-axis according to: x = 4t³ – 6t² + 3t + 2

A) 24 m/s²

B) 36 m/s²

C) 48 m/s²

D) 12 m/s²

View Solution

Velocity:

v = dx/dt = 12t² – 12t + 3

Acceleration:

a = dv/dt = 24t – 12

At t = 2 s:

a = 24(2) – 12 = 36 m/s²

Answer: B

Q2. A car moving with speed 20 m/s is brought to rest uniformly in 5 seconds. Distance travelled is:

A) 25 m

B) 50 m

C) 75 m

D) 100 m

View Solution

s = ((u + v)/2) × t

= ((20 + 0)/2) × 5

= 50 m

Answer: B

Q3. A particle starts from rest and moves with acceleration 4 m/s². Distance covered in 5th second is:

A) 10 m

B) 18 m

C) 20 m

D) 22 m

View Solution

Distance in nth second:

Sₙ = u + (a/2)(2n – 1)

= 0 + (4/2)(9)

= 18 m

Answer: B

Q4. A train 200 m long crosses a pole in 20 s. Speed of train is:

A) 5 m/s

B) 10 m/s

C) 15 m/s

D) 20 m/s

View Solution

Speed = Distance / Time

= 200 / 20

= 10 m/s

Answer: B

Q5. A body starting from rest acquires velocity 20 m/s in 4 seconds. Distance travelled is:

A) 20 m

B) 30 m

C) 40 m

D) 50 m

View Solution

s = ((u + v)/2) × t

= ((0 + 20)/2) × 4

= 40 m

Answer: C

Q6. A particle moves according to: x = t³ – 6t² + 9t

A) 1 s

B) 2 s

C) 3 s

D) Both A and C

View Solution

Velocity:

v = 3t² – 12t + 9

For change in direction:

v = 0

3(t² – 4t + 3) = 0

(t – 1)(t – 3) = 0

t = 1 s and 3 s

Answer: D

Q7. The slope of velocity-time graph gives:

A) Velocity

B) Displacement

C) Acceleration

D) Momentum

View Solution

Slope of velocity-time graph represents acceleration.

Answer: C

Q8. A body covers first half of distance with speed v and second half with speed 2v. Average speed is:

A) 3v/2

B) 4v/3

C) 2v/3

D) v

View Solution

Average speed for equal distances:

Vavg = 2v₁v₂ / (v₁ + v₂)

= 2(v)(2v)/(v + 2v)

= 4v/3

Answer: B

Q9. A body is projected vertically upward with speed 30 m/s. Time taken to reach the highest point is: (g = 10 m/s²)

A) 2 s

B) 3 s

C) 4 s

D) 5 s

View Solution

At highest point, final velocity v = 0.

Using v = u − gt:

0 = 30 − 10t

t = 3 s

Answer: B

Q10. A particle moving with initial velocity 5 m/s has acceleration 2 m/s². Distance travelled in 4 s is:

A) 24 m

B) 28 m

C) 32 m

D) 36 m

View Solution

Using s = ut + ½at²:

s = 5(4) + ½(2)(4²)

s = 20 + 16 = 36 m

Answer: D

Q11. A particle moving with velocity 30 m/s is retarded uniformly at 5 m/s². Time to stop is:

A) 5 s

B) 6 s

C) 7 s

D) 8 s

View Solution

Using:

v = u + at

0 = 30 – 5t

t = 6 s

Answer: B

Q12. The area under acceleration-time graph gives:

A) Velocity

B) Displacement

C) Force

D) Momentum

View Solution

Area under acceleration-time graph represents change in velocity.

Answer: A

Q13. A particle moves with acceleration a = 6t. If initial velocity is zero, velocity at 2 s is:

A) 6 m/s

B) 8 m/s

C) 10 m/s

D) 12 m/s

View Solution

Velocity:

v = ∫6t dt

v = 3t²

At t = 2 s:

v = 3(2²) = 12 m/s

Answer: D

Q14. A body moving with uniform acceleration has velocities 10 m/s and 30 m/s at distances 5 m and 25 m respectively from origin. Acceleration is:

A) 10 m/s²

B) 20 m/s²

C) 15 m/s²

D) 25 m/s²

View Solution

Using:

v² – u² = 2as

30² – 10² = 2a(20)

900 – 100 = 40a

800 = 40a

a = 20 m/s²

Answer: B

Q15. A particle moves along x-axis as x = 5 + 2t – 3t². The particle changes direction at:

A) 1/3 s

B) 2/3 s

C) 1 s

D) 2 s

View Solution

Velocity:

v = dx/dt = 2 – 6t

For change in direction:

v = 0

2 – 6t = 0

t = 1/3 s

Answer: A

Q16. If velocity-time graph is a straight line parallel to time axis, acceleration is:

A) Positive

B) Negative

C) Zero

D) Infinite

View Solution

Slope of velocity-time graph gives acceleration.

Parallel line means slope = 0.

Answer: C

Q17. A stone is dropped from a height of 80 m. Time taken to reach ground is (g = 10 m/s²):

A) 2 s

B) 3 s

C) 4 s

D) 5 s

View Solution

Using:

s = ½gt²

80 = 5t²

t² = 16

t = 4 s

Answer: C

Q18. A particle travels 10 m in first second and 15 m in second second. Acceleration is:

A) 2.5 m/s²

B) 5 m/s²

C) 7.5 m/s²

D) 10 m/s²

View Solution

Difference of distances in successive seconds equals acceleration.

a = 15 – 10

a = 5 m/s²

Answer: B

Q19. A body moves with velocity proportional to time: v = kt. Displacement-time graph is:

A) Straight line

B) Circle

C) Parabola

D) Hyperbola

View Solution

Since:

v = ds/dt = kt

s = ∫kt dt

s = kt²/2

This represents a parabola.

Answer: C

Q20. A ball thrown vertically upward returns to the thrower after 6 s. Its initial speed is: (g = 10 m/s²)

A) 20 m/s

B) 25 m/s

C) 30 m/s

D) 35 m/s

View Solution

Total time of flight T = 2u/g.

6 = 2u/10

u = 30 m/s

Answer: C

Q21. A particle moving along x-axis has x = t² – 4t + 4. Minimum value of x is:

A) 0

B) 1

C) 2

D) 4

View Solution

x = (t – 2)²

Minimum value occurs at t = 2

Minimum x = 0

Answer: A

Q22. A train accelerates uniformly from 10 m/s to 30 m/s in 10 s. Distance travelled is:

A) 100 m

B) 150 m

C) 200 m

D) 250 m

View Solution

Using:

s = ((u + v)/2)t

= ((10 + 30)/2) × 10

= 20 × 10

= 200 m

Answer: C

Q23. The dimensional formula of acceleration is:

A) [LT⁻¹]

B) [LT⁻²]

C) [L²T⁻²]

D) [MLT⁻²]

View Solution

Acceleration = Velocity / Time

[LT⁻¹]/[T]

= [LT⁻²]

Answer: B

Q24. A body moving with uniform acceleration covers 100 m in 5 s and 180 m in next 5 s. Acceleration is:

A) 1.6 m/s²

B) 2 m/s²

C) 3.2 m/s²

D) 4 m/s²

View Solution

Difference in distances:

180 – 100 = 80 m

For equal intervals:

Difference = a × t²

80 = a × 25

a = 3.2 m/s²

Answer: C

Q25. The speed-time graph of a particle is a straight line with negative slope. Motion is:

A) Uniform motion

B) Accelerated motion

C) Retarded motion

D) Circular motion

View Solution

Negative slope in speed-time graph indicates retardation.

Answer: C

Q26. A particle starts with velocity 5 m/s and acceleration 2 m/s². Velocity after travelling 12 m is:

A) 5 m/s

B) 7 m/s

C) 9 m/s

D) 11 m/s

View Solution

Using:

v² = u² + 2as

v² = 5² + 2(2)(12)

v² = 25 + 48

v² = 73

v ≈ 8.5 m/s

Closest option = 9 m/s

Answer: C

Q27. A body moving with speed 15 m/s comes to rest after travelling 45 m. Retardation is:

A) 1.5 m/s²

B) 2.5 m/s²

C) 3.5 m/s²

D) 4.5 m/s²

View Solution

Using:

v² = u² + 2as

0 = 15² + 2(a)(45)

0 = 225 + 90a

a = -2.5 m/s²

Retardation = 2.5 m/s²

Answer: B

Q28. A particle covers equal distances in equal intervals of time. Its motion is:

A) Uniformly accelerated

B) Uniform

C) Retarded

D) Non-uniform

View Solution

Equal distances in equal intervals define uniform motion.

Answer: B

Q29. The intercept on velocity axis in velocity-time graph represents:

A) Acceleration

B) Final velocity

C) Initial velocity

D) Displacement

View Solution

At t = 0, graph gives initial velocity.

Answer: C

Q30. A body moving with acceleration 5 m/s² increases its velocity from 10 m/s to 30 m/s. Time taken is:

A) 2 s

B) 3 s

C) 4 s

D) 5 s

View Solution

Using:

v = u + at

30 = 10 + 5t

20 = 5t

t = 4 s

Answer: C

Q31. A particle moves with constant speed in a straight line. Its acceleration is:

A) Constant

B) Increasing

C) Zero

D) Infinite

View Solution

Velocity remains constant in magnitude and direction.

Therefore acceleration is zero.

Answer: C

Q32. A body falls freely from rest. Distance covered in 3rd second is:

A) 15 m

B) 25 m

C) 35 m

D) 45 m

View Solution

Distance in nth second:

Sₙ = (g/2)(2n − 1)

= (10/2)(2×3 − 1)

= 5 × 5

= 25 m

Answer: B

Q33. A particle has acceleration-time graph parallel to time axis above it. Motion is:

A) Uniform velocity

B) Constant acceleration

C) Variable acceleration

D) Retardation

View Solution

A horizontal line above time axis means acceleration is constant and positive.

Answer: B

Q34. A body moving at 25 m/s is slowed uniformly to 5 m/s in 10 s. Acceleration is:

A) -1 m/s²

B) -2 m/s²

C) -3 m/s²

D) -4 m/s²

View Solution

Using:

a = (v − u)/t

= (5 − 25)/10

= -20/10

= -2 m/s²

Answer: B

Q35. If displacement-time graph is a straight line, velocity is:

A) Variable

B) Zero

C) Constant

D) Infinite

View Solution

Slope of displacement-time graph gives velocity.

Straight line means constant slope.

Therefore velocity is constant.

Answer: C

Q36. A particle moves such that v = 3t + 2. Displacement in first 2 seconds is:

A) 8 m

B) 10 m

C) 12 m

D) 14 m

View Solution

s = ∫(3t + 2)dt from 0 to 2

= [3t²/2 + 2t]₀²

= (6 + 4)

= 10 m

Answer: B

Q37. A train moving at 72 km/h is brought to rest in 20 s. Retardation is:

A) 0.5 m/s²

B) 1 m/s²

C) 1.5 m/s²

D) 2 m/s²

View Solution

72 km/h = 20 m/s

a = (0 − 20)/20

= -1 m/s²

Retardation = 1 m/s²

Answer: B

Q38. The SI unit of velocity is:

A) m

B) m/s

C) m/s²

D) km/h

View Solution

SI unit of velocity is metre per second.

Answer: B

Q39. A particle starts from rest with acceleration 3 m/s². Velocity after 6 s is:

A) 12 m/s

B) 15 m/s

C) 18 m/s

D) 21 m/s

View Solution

Using:

v = u + at

= 0 + 3 × 6

= 18 m/s

Answer: C

Q40. A body covers 20 m in first 2 s and 40 m in next 2 s. Motion is:

A) Uniform

B) Accelerated

C) Retarded

D) Circular

View Solution

Distance covered increases in equal intervals of time.

This indicates accelerated motion.

Answer: B

Q41. The area under velocity-time graph represents:

A) Acceleration

B) Force

C) Displacement

D) Momentum

View Solution

Area under velocity-time graph gives displacement.

Answer: C

Q42. A particle moves with acceleration -4 m/s². If initial velocity is 20 m/s, time to stop is:

A) 2 s

B) 4 s

C) 5 s

D) 8 s

View Solution

Using:

v = u + at

0 = 20 – 4t

t = 5 s

Answer: C

Q43. A body travels with uniform acceleration. Ratio of distances covered in 1st, 2nd and 3rd seconds is:

A) 1 : 2 : 3

B) 1 : 3 : 5

C) 1 : 4 : 9

D) 2 : 3 : 4

View Solution

Distance in nth second is proportional to:

(2n − 1)

Therefore ratio is:

1 : 3 : 5

Answer: B

Q44. A particle has constant velocity. Which statement is true?

A) Acceleration constant

B) Acceleration zero

C) Force infinite

D) Speed variable

View Solution

Constant velocity means no change in velocity.

Hence acceleration is zero.

Answer: B

Q45. A particle moves according to x = 2t² + 3t + 1. Velocity at t = 2 s is:

A) 7 m/s

B) 9 m/s

C) 11 m/s

D) 13 m/s

View Solution

Velocity:

v = dx/dt

= 4t + 3

At t = 2:

v = 8 + 3

v = 11 m/s

Answer: C

Q46. A body moving uniformly covers 120 m in 8 s. Speed is:

A) 10 m/s

B) 12 m/s

C) 15 m/s

D) 20 m/s

View Solution

Speed = Distance / Time

= 120 / 8

= 15 m/s

Answer: C

Q47. A particle starts from rest and moves with acceleration 2 m/s². Distance travelled in 10 s is:

A) 50 m

B) 100 m

C) 150 m

D) 200 m

View Solution

Using:

s = ½at²

= ½ × 2 × 10²

= 100 m

Answer: B

Q48. The graph of displacement versus time for uniform motion is:

A) Circle

B) Straight line

C) Parabola

D) Hyperbola

View Solution

Uniform motion means constant velocity.

Displacement-time relation becomes linear.

Answer: B

Q49. A body initially at rest acquires acceleration 4 m/s². Distance covered in 3 s is:

A) 12 m

B) 16 m

C) 18 m

D) 20 m

View Solution

Using:

s = ½at²

= ½ × 4 × 3²

= 2 × 9

= 18 m

Answer: C

Q50. A particle moving with speed 40 m/s is uniformly retarded at 8 m/s². Distance travelled before stopping is:

A) 80 m

B) 100 m

C) 120 m

D) 140 m

View Solution

Using:

v² = u² + 2as

0 = 40² + 2(-8)s

0 = 1600 – 16s

16s = 1600

s = 100 m

Answer: B

Motion in a Straight Line PYQ Practice

Class 11 Physics | JEE Main, JEE Advanced, NEET

Q1. Two cars are 300 m apart and move towards each other with speeds 20 m/s and 10 m/s. Both apply brakes simultaneously with retardation 2 m/s². Find the separation when both stop.

JEE Main • 2024

A) 25 m

B) 50 m

C) 75 m

D) 100 m

Answer: B

Q2. A particle moves along x-axis with position x = 3t² − 2t + 5. Its velocity at t = 4 s is:

JEE Main • 2024

A) 20 m/s

B) 22 m/s

C) 24 m/s

D) 26 m/s

Answer: B

Q3. The velocity-time graph of a particle is a straight line passing through origin with slope 4. Distance covered in 5 s is:

JEE Main • 2023

A) 25 m

B) 50 m

C) 75 m

D) 100 m

Answer: B

Q4. A body moves with uniform acceleration. Its velocity changes from 10 m/s to 30 m/s in 5 s. Acceleration is:

JEE Main • 2023

A) 2 m/s²

B) 4 m/s²

C) 6 m/s²

D) 8 m/s²

Answer: B

Q5. A bullet moving with speed u enters a wooden block and its speed becomes u/3 after penetrating 4 cm. Assuming constant retardation, total penetration before stopping is:

JEE Main • 2022

A) 4.5 cm

B) 5.0 cm

C) 6.0 cm

D) 8.0 cm

Answer: A

Q6. A stone is thrown vertically upward with speed 40 m/s. Taking g = 10 m/s², time after which it returns to starting point is:

JEE Main • 2022

A) 4 s

B) 6 s

C) 8 s

D) 10 s

Answer: C

Q7. A particle has velocity v = 4t − 2. Its displacement from t = 0 to t = 3 s is:

JEE Main • 2021

A) 12 m

B) 15 m

C) 18 m

D) 21 m

Answer: A

Q8. A train of length 200 m crosses a pole in 10 s. Its speed is:

JEE Main • 2021

A) 10 m/s

B) 15 m/s

C) 20 m/s

D) 25 m/s

Answer: C

Q9. A particle moving in a straight line covers first half of distance with speed 20 m/s and second half with speed 30 m/s. Average speed is:

JEE Main • 2020

A) 22 m/s

B) 24 m/s

C) 25 m/s

D) 26 m/s

Answer: B

Q10. The distance travelled by a freely falling body in 3rd second is: (g = 10 m/s²)

JEE Main • 2020

A) 15 m

B) 20 m

C) 25 m

D) 30 m

Answer: C

Q11. For a particle moving along x-axis, x = t³ − 6t² + 9t. The particle changes direction at:

JEE Main • 2019

A) 1 s only

B) 3 s only

C) 1 s and 3 s

D) 2 s

Answer: C

Q12. A body starting from rest moves with acceleration 2 m/s². Its average velocity in first 5 s is:

JEE Main • 2019

A) 2 m/s

B) 5 m/s

C) 10 m/s

D) 20 m/s

Answer: B

Q13. A car moving with speed 72 km/h is brought to rest in 10 s. Retardation is:

JEE Main • 2018

A) 1 m/s²

B) 2 m/s²

C) 3 m/s²

D) 4 m/s²

Answer: B

Q14. A particle covers 20 m in first 2 s and 60 m in next 4 s. Average speed for total journey is:

JEE Main • 2018

A) 10 m/s

B) 12 m/s

C) 13.33 m/s

D) 15 m/s

Answer: C

Q15. A particle moves with acceleration a = 6t. If initial velocity is zero, velocity at t = 3 s is:

JEE Advanced • 2017

A) 18 m/s

B) 27 m/s

C) 36 m/s

D) 54 m/s

Answer: B

Q16. The velocity of a particle is v = 2x, where x is displacement. If x = 1 m at t = 0, then acceleration at x = 2 m is:

JEE Advanced • 2016

A) 4 m/s²

B) 6 m/s²

C) 8 m/s²

D) 10 m/s²

Answer: C

Q17. A particle moves such that x = 2t³ − 9t² + 12t. At which time is velocity zero?

JEE Advanced • 2015

A) 1 s, 2 s

B) 1 s, 3 s

C) 2 s, 3 s

D) 1 s, 4 s

Answer: A

Q18. A body is thrown vertically upward with speed u. Ratio of time of ascent to total time of flight is:

JEE Advanced • 2014

A) 1:1

B) 1:2

C) 2:1

D) 1:4

Answer: B

Q19. A particle starts from rest and moves with uniform acceleration. Ratio of distances travelled in 1st, 2nd and 3rd seconds is:

AIEEE • 2012

A) 1:2:3

B) 1:3:5

C) 1:4:9

D) 2:3:4

Answer: B

Q20. A particle moves with constant velocity. Its acceleration is:

AIEEE • 2011

A) constant non-zero

B) zero

C) infinite

D) variable

Answer: B

Q21. The slope of displacement-time graph represents:

AIEEE • 2010

A) acceleration

B) velocity

C) distance

D) force

Answer: B

Q22. Area under velocity-time graph gives:

AIEEE • 2009

A) acceleration

B) displacement

C) velocity

D) jerk

Answer: B

Q23. A body is moving with speed 10 m/s. It accelerates at 2 m/s² for 5 s. Final speed is:

AIEEE • 2008

A) 15 m/s

B) 18 m/s

C) 20 m/s

D) 25 m/s

Answer: C

Q24. A particle moves with uniform retardation and stops in 4 s from speed 20 m/s. Distance travelled is:

AIEEE • 2007

A) 20 m

B) 30 m

C) 40 m

D) 50 m

Answer: C

Q25. A body falls freely from rest for 4 s. Distance covered in last second is: (g = 10 m/s²)

NEET • 2024

A) 25 m

B) 30 m

C) 35 m

D) 40 m

Answer: C

Q26. If a body covers equal distances in equal intervals of time, its motion is:

NEET • 2023

A) uniform

B) uniformly accelerated

C) retarded

D) oscillatory

Answer: A

Q27. A stone dropped from a height h reaches ground in 3 s. Taking g = 10 m/s², h is:

NEET • 2022

A) 30 m

B) 45 m

C) 60 m

D) 90 m

Answer: B

Q28. A particle moves with velocity v = 5 + 2t. Displacement in first 4 s is:

NEET • 2021

A) 24 m

B) 28 m

C) 32 m

D) 36 m

Answer: D

Q29. Velocity-time graph of a body is parallel to time axis. The body has:

NEET • 2020

A) zero velocity

B) constant velocity

C) constant acceleration

D) variable acceleration

Answer: B

Q30. A body moving with initial velocity 5 m/s and acceleration 3 m/s² travels for 4 s. Distance covered is:

NEET • 2019

A) 36 m

B) 40 m

C) 44 m

D) 48 m

Answer: C

Q31. A ball is thrown vertically upward with speed 20 m/s. Maximum height reached is: (g = 10 m/s²)

NEET • 2018

A) 10 m

B) 20 m

C) 30 m

D) 40 m

Answer: B

Q32. A body moving with speed 15 m/s is stopped in 3 s. Retardation is:

NEET • 2017

A) 3 m/s²

B) 5 m/s²

C) 7 m/s²

D) 9 m/s²

Answer: B

Q33. For uniformly accelerated motion, v² − u² is equal to:

NEET • 2016

A) as

B) 2as

C) a/s

D) 2a/s

Answer: B

Q34. A car covers first half of distance at 40 km/h and second half at 60 km/h. Average speed is:

NEET • 2015

A) 45 km/h

B) 48 km/h

C) 50 km/h

D) 52 km/h

Answer: B

Q35. A particle starts from rest. Distance covered in first 10 s is S1 and first 20 s is S2. S2:S1 is:

AIPMT • 2014

A) 2:1

B) 3:1

C) 4:1

D) 5:1

Answer: C

Q36. A particle changes velocity from 10 m/s to 20 m/s while covering 75 m. Acceleration is:

AIPMT • 2012

A) 1 m/s²

B) 2 m/s²

C) 3 m/s²

D) 4 m/s²

Answer: B

Q37. A body falls freely from rest. Its velocity after 5 s is: (g = 10 m/s²)

AIPMT • 2011

A) 25 m/s

B) 40 m/s

C) 50 m/s

D) 100 m/s

Answer: C

Q38. If displacement-time graph is a parabola, motion may have:

AIPMT • 2010

A) uniform velocity

B) uniform acceleration

C) zero acceleration

D) infinite velocity

Answer: B

Q39. A scooterist chases a bus moving with constant speed. The minimum condition to catch it is that scooterist's speed should be:

AIPMT • 2009

A) less than bus speed

B) equal to bus speed

C) greater than bus speed

D) zero

Answer: C

Q40. A body travels 100 m in 5 s and 200 m in next 5 s. Its motion is:

AIPMT • 2008

A) uniform

B) accelerated

C) retarded

D) at rest

Answer: B

Q41. A particle moves along a straight line with x = 5t − t². Its velocity becomes zero at:

JEE Main • 2026

A) 1.5 s

B) 2.0 s

C) 2.5 s

D) 5.0 s

Answer: C

Q42. Two particles start from same point with speeds 10 m/s and 15 m/s in same direction. Separation after 8 s is:

JEE Main • 2025

A) 20 m

B) 30 m

C) 40 m

D) 50 m

Answer: C

Q43. For a particle, relation between time and distance is t = ax² + bx. If velocity is v, acceleration is proportional to:

JEE Main • 2024

A) v

B) v²

C) v³

D) 1/v

Answer: C

Q44. A juggler throws balls vertically upward with same speed at regular interval. At highest point velocity of each ball is:

JEE Main • 2023

A) u

B) u/2

C) zero

D) g

Answer: C

Q45. A balloon rises with constant velocity 10 m/s. A stone is dropped from it. Initial velocity of stone relative to ground is:

JEE Main • 2022

A) zero

B) 10 m/s upward

C) 10 m/s downward

D) 20 m/s upward

Answer: B

Q46. A train crosses a platform of length 300 m in 25 s and a pole in 10 s. Speed of train is:

JEE Main • 2021

A) 15 m/s

B) 20 m/s

C) 25 m/s

D) 30 m/s

Answer: B

Q47. A body thrown vertically upward has velocity-time graph as:

JEE Main • 2020

A) straight line positive slope

B) straight line negative slope

C) parabola

D) circle

Answer: B

Q48. A body with initial speed 10 m/s accelerates uniformly at 4 m/s². Distance in 5 s is:

NEET • 2026

A) 50 m

B) 75 m

C) 100 m

D) 125 m

Answer: C

Q49. If acceleration is zero, velocity is:

NEET • 2025

A) always zero

B) constant

C) increasing

D) decreasing

Answer: B

Q50. A particle covers 30 m in first 3 s and 50 m in next 2 s. Average speed is:

NEET • 2024

A) 14 m/s

B) 15 m/s

C) 16 m/s

D) 18 m/s

Answer: C